PROBLEM 01

(1 point)

Why is the following function discontinuous at x=0�=0?

 

f(x)=exx2if x<0if x0�(�)={��if �<0�2if �≥0

 

(a) f(0)�(0) does not exist.
(b) limx0f(x)lim�→0�(�) does not exist (or is infinite).
(c) Both (a) and (b).
(d) f(0)�(0) and limx0f(x)lim�→0�(�) exist, but they are not equal.

 

台大WEBWORK 微積分1:11~14組 【2.5: Pr

 

 

PROBLEM 02

(1 point)

Which of the following is a function that has a jump discontinuity at x=2�=2 and a removable discontinuity at x=4�=4, but is continuous elsewhere?

(a) f(x)=2(x2)(x4)�(�)=2(�−2)(�−4).

(b) f(x)=1x33if x2if 2<x<4 or x>4if x=4�(�)={1if �≤2�−3if 2<�<4 or �>43if �=4.

(c) f(x)=2x21x24xif x2if x>2�(�)={2−�2if �≤21�2−4�if �>2.

台大WEBWORK 微積分1:11~14組 【2.5: Pr

 

PROBLEM 03

(1 point)

If f(x)=x3x2+x�(�)=�3−�2+�, is there a number c such that f(c)=10�(�)=10?
Answer "y" for yes or "n" for no below.

台大WEBWORK 微積分1:11~14組 【2.5: Pr

PROBLEM 04

(1 point) Find the value of the constant c that makes the following function continuous on (,)(−∞,∞).

f(x)={cx+8cx28if x(,2]if x(2,)�(�)={��+8if �∈(−∞,2]��2−8if �∈(2,∞)

 

c=�= 

 

台大WEBWORK 微積分1:11~14組 【2.5: Pr

 

PROBLEM 05

(1 point)

For the functions below that have a removable discontinuity at x=a�=� [if the function does not have a removable discontinuity, type in "n" below], state the value of g(a)�(�), where g(x)�(�) agrees with f(x)�(�) for xa�≠� and is continuous everywhere.

(a) f(x)=x22x8x+2�(�)=�2−2�−8�+2, a=2�=−2

(b) f(x)=x7|x7|�(�)=�−7|�−7|, a=7�=7

(c) f(x)=x3+64x+4�(�)=�3+64�+4, a=4�=−4

(d) f(x)=3x9x�(�)=3−�9−�, a=9�=9

(a) 
(b) 
(c) 
(d) 

 

台大WEBWORK 微積分1:11~14組 【2.5: Pr

台大WEBWORK 微積分1:11~14組 【2.5: Pr

 

 

webwork、calculus、微積分、calculus微積分解答、微積分詳解、台大微積分、微積分模組班、微積分乙

 

 

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